What is the integral of (2cos(x)-3sec(x)tan(x)) ?

The integral of (2cos(x)-3sec(x)tan(x)) is 2sin(x)-3sec(x)+C

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integral of (2cos(x)-3sec(x)tan(x))

\int (2 cos (x) - 3 sec (x) tan (x)) d x

2 sin (x) - 3 sec (x) + C

Solution steps

\int 2 cos (x) - 3 sec (x) tan (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 cos (x) d x - \int 3 sec (x) tan (x) d x

\int 2 cos (x) d x = 2 sin (x)

\int 3 sec (x) tan (x) d x = 3 sec (x)

= 2 sin (x) - 3 sec (x)

Add a constant to the solution

= 2 sin (x) - 3 sec (x) + C

\frac{d}{d x} ((\frac{sin ( x )}{1 + cos ( x )})^{2})

f (x) = x^{2} - 4 x

\frac{45}{0.01 x ^{2} + 1}

\frac{\partial}{\partial x} (x^{3} - 15 x y + y^{3})

x^{3}, 2 x - 12.3 x^{2}

What is the integral of (2cos(x)-3sec(x)tan(x)) ?
The integral of (2cos(x)-3sec(x)tan(x)) is 2sin(x)-3sec(x)+C