What is (\partial)/(\partial x)(2x^2+1) ?

The answer to (\partial)/(\partial x)(2x^2+1) is 4x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2x^2+1)

\frac{\partial}{\partial x} (2 x^{2} + 1)

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (1) = 0

= 4 x + 0

Simplify

= 4 x

x \to 6 lim (\frac{5}{6} + 9 (- \frac{2}{3}))

\frac{d}{d x} (ln (x + 7 + x^{2}))

k = 1 \sum \infty \frac{1}{4 k ^{2} - 1}

x \to 0 + lim ((x)^{x})

\frac{d}{d x} (3 ln (x) - 12 sin (x))

What is (\partial)/(\partial x)(2x^2+1) ?
The answer to (\partial)/(\partial x)(2x^2+1) is 4x