What is area 11cos(θ),5+cos(θ) ?

The answer to area 11cos(θ),5+cos(θ) is 10sqrt(3)+(20pi)/3

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area 11cos(θ),5+cos(θ)

area

11 cos (θ), 5 + cos (θ)

103 + \frac{20 π}{3}

Decimal

38.26445 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{3}}^{\frac{5 π}{3}} ∣ 11 cos (θ) - (5 + cos (θ)) ∣ d θ

Solve

\int_{\frac{π}{3}}^{\frac{5 π}{3}} ∣ 11 cos (θ) - (5 + cos (θ)) ∣ d θ : 103 + \frac{20 π}{3}

The area is:

= 103 + \frac{20 π}{3}

\frac{d}{d x} (ln (3^{x} sec^{3} (4 x)))

\int_{- 2}^{5} 2 e^{x} (5 x^{2} + 3) d x

\int x 4 + x d x

f (x) = x^{3} - 3 x^{2} + 5, at x = - 1

\int_{0}^{6} 2

What is area 11cos(θ),5+cos(θ) ?
The answer to area 11cos(θ),5+cos(θ) is 10sqrt(3)+(20pi)/3