What is the derivative of (x^2-3x^5) ?

The derivative of (x^2-3x^5) is 5(x^2-3x)^4(2x-3)

What is the first derivative of (x^2-3x^5) ?

The first derivative of (x^2-3x^5) is 5(x^2-3x)^4(2x-3)

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\frac{d}{d x} ((x^{2} - 3 x)^{5})

5 (x^{2} - 3 x)^{4} (2 x - 3)

Solution steps

\frac{d}{d x} ((x^{2} - 3 x)^{5})

Apply the chain rule:

5 (x^{2} - 3 x)^{4} \frac{d}{d x} (x^{2} - 3 x)

= 5 (x^{2} - 3 x)^{4} \frac{d}{d x} (x^{2} - 3 x)

\frac{d}{d x} (x^{2} - 3 x) = 2 x - 3

= 5 (x^{2} - 3 x)^{4} (2 x - 3)

(12 x^{2} + y - 1) d x - (6 y - x) d y = 0, y (1) = 0

\frac{d}{d x} (e^{2 x + 3 y})

\frac{d y}{d x}, y = 5^{x}

\frac{d}{d x} (16 x^{2} + 9)

\int_{- 1}^{1} 1.5 x^{3} d x

What is the derivative of (x^2-3x^5) ?
The derivative of (x^2-3x^5) is 5(x^2-3x)^4(2x-3)
What is the first derivative of (x^2-3x^5) ?
The first derivative of (x^2-3x^5) is 5(x^2-3x)^4(2x-3)