What is the integral of 1/((x+2)^2) ?

The integral of 1/((x+2)^2) is -1/(x+2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/((x+2)^2)

\int \frac{1}{( x + 2 ) ^{2}} d x

- \frac{1}{x + 2} + C

Solution steps

\int \frac{1}{( x + 2 ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = x + 2

= - \frac{1}{x + 2}

Add a constant to the solution

= - \frac{1}{x + 2} + C

\int \frac{1}{( x + 1 ) ( x + 2 ) ^{2}} d x

\frac{d}{d x} (ln (6 x^{3} + 3 x^{2} - 2 x))

f (x) = x + 2, at (x = 4)

\int 2 y e^{y^{2}} d y

\int x^{2} (x^{2} + 1) d x