What is the integral of (xe^{x^2}) ?

The integral of (xe^{x^2}) is 1/2 e^{x^2}+C

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integral of (xe^{x^2})

\int (x e^{x^{2}}) d x

\frac{1}{2} e^{x^{2}} + C

Solution steps

\int x e^{x^{2}} d x

Apply u-substitution

: \int \frac{e ^{u}}{2} d u

= \int \frac{e ^{u}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{2} e^{u}

Substitute back

u = x^{2}

= \frac{1}{2} e^{x^{2}}

Add a constant to the solution

= \frac{1}{2} e^{x^{2}} + C

\frac{d}{d x} (ln (x^{2} + 12))

csc (x), at x = \frac{π}{6}

x cos (\frac{π x}{2})

e^{- \frac{x ^{2}}{2}}

\frac{d}{d x} (e^{s x})

What is the integral of (xe^{x^2}) ?
The integral of (xe^{x^2}) is 1/2 e^{x^2}+C