What is the first derivative of 8x-1 ?

The first derivative of 8x-1 is 8

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derivative of 8x-1

\frac{d}{d x} (8 x - 1)

8

Solution steps

\frac{d}{d x} (8 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (1)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (1) = 0

= 8 - 0

Simplify

= 8

y^{^{''}} + 9 y = 0, y (0) = 5, y^{^{'}} (0) = 1

x \to 9 lim (\frac{7 x}{x - 9})

\int sec^{2} (3 x + 2) d x

\int \frac{2 x - 4}{x ^{2} - x} d x

y^{^{''}} + 10 y^{^{'}} + 25 y = 5 e^{- (5 t)}