What is the integral from 0 to pi of 8sin(x) ?

The integral from 0 to pi of 8sin(x) is 16

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integral from 0 to pi of 8sin(x)

\int_{0}^{π} 8 sin (x) d x

16

Solution steps

\int_{0}^{π} 8 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 8 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 8 \cdot 2

Simplify

= 16

(0, 3), (6, 9)

\int 5 x e^{12 x} d x

y^{^{'}} + y = y^{- \frac{1}{2}}

\int_{- 2}^{1} \frac{1}{( x - 1 ) ^{3}} d x

f (x) = 1 - 2 x

What is the integral from 0 to pi of 8sin(x) ?
The integral from 0 to pi of 8sin(x) is 16