What is (\partial)/(\partial x)((sin(x-y))(-1.1)) ?

The answer to (\partial)/(\partial x)((sin(x-y))(-1.1)) is -1.1cos(x-y)

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(\partial)/(\partial x)((sin(x-y))(-1.1))

\frac{\partial}{\partial x} ((sin (x - y)) (- 1.1))

- 1.1 cos (x - y)

Solution steps

\frac{\partial}{\partial x} ((sin (x - y)) (- 1.1))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 1.1 \frac{\partial}{\partial x} (sin (x - y))

Apply the chain rule:

cos (x - y) \frac{\partial}{\partial x} (x - y)

= cos (x - y) \frac{\partial}{\partial x} (x - y)

\frac{\partial}{\partial x} (x - y) = 1

= - 1.1 cos (x - y) \cdot 1

Simplify

= - 1.1 cos (x - y)

y = \frac{4}{3} π r^{3}

ln (4)

\int \frac{x ^{2} - 1}{x ^{3} + x ^{2} + x} d x

f (x) = x^{2} - 7 x + 5, at x = 4

\int \frac{2 x ^{2} + 6 x - 5 x}{3 x ^{2}} d x

What is (\partial)/(\partial x)((sin(x-y))(-1.1)) ?
The answer to (\partial)/(\partial x)((sin(x-y))(-1.1)) is -1.1cos(x-y)