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Popular >

2y^{''}+8y=0

Solution

2 y^{^{''}} + 8 y = 0

Solution

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

2 y^{''} (t) + 8 y = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

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Frequently Asked Questions (FAQ)

What is the solution for 2y^{''}+8y=0 ?
The solution for 2y^{''}+8y=0 is y=c_{1}cos(2t)+c_{2}sin(2t)