What is the sum from n=0 to infinity of (-1/2)^{n-1} ?

The sum from n=0 to infinity of (-1/2)^{n-1} is converges

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sum from n=0 to infinity of (-1/2)^{n-1}

n = 0 \sum \infty (- \frac{1}{2})^{n - 1}

converges

Solution steps

n = 0 \sum \infty (- \frac{1}{2})^{n - 1}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} (cos (\frac{1}{x ^{2}}))

f (t) = \frac{t}{2}

\frac{d}{d x} (x^{0.25})

\frac{d}{d x} (4 x - 2)

x \to + 1 lim (a r cos (x))

What is the sum from n=0 to infinity of (-1/2)^{n-1} ?
The sum from n=0 to infinity of (-1/2)^{n-1} is converges