What is (\partial ^2)/(\partial x^2)(x^3+3xy^2) ?

The answer to (\partial ^2)/(\partial x^2)(x^3+3xy^2) is 6x

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(\partial ^2)/(\partial x^2)(x^3+3xy^2)

\frac{\partial ^{2}}{\partial x ^{2}} (x^{3} + 3 x y^{2})

6 x

Solution steps

\frac{\partial ^{2}}{\partial x ^{2}} (x^{3} + 3 x y^{2})

\frac{\partial}{\partial x} (x^{3} + 3 x y^{2}) = 3 x^{2} + 3 y^{2}

= \frac{\partial}{\partial x} (3 x^{2} + 3 y^{2})

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2}) = 6 x

= 6 x

\frac{1}{( s - 3 ) ^{3}}

\frac{d v}{d t} = - k t v^{2}

f (x) = 15 x ln (8 x)

\frac{\partial}{\partial x} (- 6 + 5 - 6 x)

\frac{d}{d x} (\frac{2}{x + 3})

What is (\partial ^2)/(\partial x^2)(x^3+3xy^2) ?
The answer to (\partial ^2)/(\partial x^2)(x^3+3xy^2) is 6x