What is the tangent of f(x)=x^2-2,(-3,7) ?

The tangent of f(x)=x^2-2,(-3,7) is y=-6x-11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2-2,(-3,7)

tangent of

f (x) = x^{2} - 2, (- 3, 7)

y = - 6 x - 11

Solution steps

Find the slope of

f (x) = x^{2} - 2 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 2

(- 3, 7) : m = - 6

Find the line with slope m=

- 6

and passing through

(- 3, 7) : y = - 6 x - 11

y = - 6 x - 11

\frac{( x + 1 ) d y}{d x} = x + 6

\int cos^{12} (x) sin (x) d x

\frac{d}{d x} (- 1 + e^{2 x})

y = e^{x}, y = e^{3 x}, x = 0, x = ln (4)

\int_{0}^{1} 7 cos (4 x) d x

What is the tangent of f(x)=x^2-2,(-3,7) ?
The tangent of f(x)=x^2-2,(-3,7) is y=-6x-11