What is the derivative of f(x)=(x^2-3)/2 ?

The derivative of f(x)=(x^2-3)/2 is x

What is the first derivative of f(x)=(x^2-3)/2 ?

The first derivative of f(x)=(x^2-3)/2 is x

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derivative of

f (x) = \frac{x ^{2} - 3}{2}

x

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 3}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d}{d x} (x^{2}) - \frac{d}{d x} (3))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3) = 0

= \frac{1}{2} (2 x - 0)

Simplify

\frac{1}{2} (2 x - 0) : x

= x

y^{^{'}} = t y^{3}

x \to 8 lim (cos (\frac{1}{x - 8}))

x \to \frac{π}{2} lim (2)

\frac{\partial}{\partial y} (- ln (cos (y)))

\int e^{6 x} sin (5 x) d x

What is the derivative of f(x)=(x^2-3)/2 ?
The derivative of f(x)=(x^2-3)/2 is x
What is the first derivative of f(x)=(x^2-3)/2 ?
The first derivative of f(x)=(x^2-3)/2 is x