What is the tangent of f(x)= 2/x ,\at x=4 ?

The tangent of f(x)= 2/x ,\at x=4 is y=-1/8 x+1

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tangent of f(x)= 2/x ,\at x=4

tangent of

f (x) = \frac{2}{x}, at x = 4

y = - \frac{1}{8} x + 1

Solution steps

Find the tangent point:

(4, \frac{1}{2})

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

x = 4 : m = - \frac{1}{8}

Find the line with slope m=

- \frac{1}{8}

and passing through

(4, \frac{1}{2}) : y = - \frac{1}{8} x + 1

y = - \frac{1}{8} x + 1

\frac{d}{d t} (\frac{1}{t ^{4} + 1})

\int_{0}^{2} (2 - x^{2}) d x

\frac{\partial}{\partial z} (\frac{x}{z} + \frac{y}{z})

\int (x^{2} - 3 x + 4) d x

\int - tan (x) sin (x) d x

What is the tangent of f(x)= 2/x ,\at x=4 ?
The tangent of f(x)= 2/x ,\at x=4 is y=-1/8 x+1