What is (\partial)/(\partial x)(48x^5y^7-35x^4y^6) ?

The answer to (\partial)/(\partial x)(48x^5y^7-35x^4y^6) is 240y^7x^4-140y^6x^3

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(\partial)/(\partial x)(48x^5y^7-35x^4y^6)

\frac{\partial}{\partial x} (48 x^{5} y^{7} - 35 x^{4} y^{6})

240 y^{7} x^{4} - 140 y^{6} x^{3}

Solution steps

\frac{\partial}{\partial x} (48 x^{5} y^{7} - 35 x^{4} y^{6})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (48 x^{5} y^{7}) - \frac{\partial}{\partial x} (35 x^{4} y^{6})

\frac{\partial}{\partial x} (48 x^{5} y^{7}) = 240 y^{7} x^{4}

\frac{\partial}{\partial x} (35 x^{4} y^{6}) = 140 y^{6} x^{3}

= 240 y^{7} x^{4} - 140 y^{6} x^{3}

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What is (\partial)/(\partial x)(48x^5y^7-35x^4y^6) ?
The answer to (\partial)/(\partial x)(48x^5y^7-35x^4y^6) is 240y^7x^4-140y^6x^3