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Popular >

integral of 1+cos(θ)

Solution

\int 1 + cos (θ) d θ

Solution

θ + sin (θ) + C

Solution steps

\int 1 + cos (θ) d θ

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d θ + \int cos (θ) d θ

\int 1 d θ = θ

\int cos (θ) d θ = sin (θ)

= θ + sin (θ)

Add a constant to the solution

= θ + sin (θ) + C

Popular Examples

tangent of f(x)=-7x^4+11x^2-4,\at x=1 tangent of

f (x) = - 7 x^{4} + 11 x^{2} - 4, at x = 1

integral of 1/(sqrt(x^2+4x-1))

\int \frac{1}{x ^{2} + 4 x - 1} d x

integral of 1/(\sqrt[3]{x-3)}

derivative of x^2+25 derivative of

x^{2} + 25

d/(dy)(e^{x^2-y^2}cos(2xy))

\frac{d}{d y} (e^{x^{2} - y^{2}} cos (2 x y))

Frequently Asked Questions (FAQ)

What is the integral of 1+cos(θ) ?
The integral of 1+cos(θ) is θ+sin(θ)+C