What is area y=e^x,y=e^{2x},x=0,x=ln(4) ?

The answer to area y=e^x,y=e^{2x},x=0,x=ln(4) is 9/2

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area y=e^x,y=e^{2x},x=0,x=ln(4)

area

y = e^{x}, y = e^{2 x}, x = 0, x = ln (4)

\frac{9}{2}

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{0}^{l n (4)} e^{x} - e^{2 x} d x

Solve

\int_{0}^{l n (4)} e^{x} - e^{2 x} d x : \frac{9}{2}

The area is:

= \frac{9}{2}

\frac{\partial}{\partial y} (y^{x} - ln (x^{3} y + 6 x))

x \to - 4 + lim (\frac{- 6 x}{x + 4})

\frac{\partial}{\partial x} (arctan (\frac{1}{x}))

\int e^{- s t} t sin (t) d t

f (x) = \frac{2}{( 1 - x ) ^{2}}

What is area y=e^x,y=e^{2x},x=0,x=ln(4) ?
The answer to area y=e^x,y=e^{2x},x=0,x=ln(4) is 9/2