What is the derivative of (2cos(2x+sin(3x))^2) ?

The derivative of (2cos(2x+sin(3x))^2) is 2(2cos(2x)+sin(3x))(-4sin(2x)+cos(3x)*3)

What is the first derivative of (2cos(2x+sin(3x))^2) ?

The first derivative of (2cos(2x+sin(3x))^2) is 2(2cos(2x)+sin(3x))(-4sin(2x)+cos(3x)*3)

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\frac{d}{d x} ((2 cos (2 x) + sin (3 x))^{2})

2 (2 cos (2 x) + sin (3 x)) (- 4 sin (2 x) + cos (3 x) \cdot 3)

Solution steps

\frac{d}{d x} ((2 cos (2 x) + sin (3 x))^{2})

Apply the chain rule:

2 (2 cos (2 x) + sin (3 x)) \frac{d}{d x} (2 cos (2 x) + sin (3 x))

= 2 (2 cos (2 x) + sin (3 x)) \frac{d}{d x} (2 cos (2 x) + sin (3 x))

\frac{d}{d x} (2 cos (2 x) + sin (3 x)) = - 4 sin (2 x) + cos (3 x) \cdot 3

= 2 (2 cos (2 x) + sin (3 x)) (- 4 sin (2 x) + cos (3 x) \cdot 3)

e^{X}

\int y^{2} x d y

x y y^{^{'}} = 4 x^{2} + y^{2}

- 3 x^{\frac{2}{3}}

\frac{d}{d x} (\frac{sin ( x ) - 1}{cos ( x ) + 1})

What is the derivative of (2cos(2x+sin(3x))^2) ?
The derivative of (2cos(2x+sin(3x))^2) is 2(2cos(2x)+sin(3x))(-4sin(2x)+cos(3x)*3)
What is the first derivative of (2cos(2x+sin(3x))^2) ?
The first derivative of (2cos(2x+sin(3x))^2) is 2(2cos(2x)+sin(3x))(-4sin(2x)+cos(3x)*3)