What is the derivative of sqrt(x)+1 ?

The derivative of sqrt(x)+1 is 1/(2sqrt(x))

What is the first derivative of sqrt(x)+1 ?

The first derivative of sqrt(x)+1 is 1/(2sqrt(x))

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derivative of

x + 1

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (1)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (1) = 0

= \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x}

\frac{d}{d x} (∣ x ∣^{a})

\int \frac{1}{x ^{2} 36 x ^{2} - 1} d x

x^{s i n (x)}

f (x) = \frac{3 x}{( x + 1 ) ^{2}}, at x = 0

f (x) = \frac{1}{x ^{2} + 1}

What is the derivative of sqrt(x)+1 ?
The derivative of sqrt(x)+1 is 1/(2sqrt(x))
What is the first derivative of sqrt(x)+1 ?
The first derivative of sqrt(x)+1 is 1/(2sqrt(x))