What is the integral of 5/(x-6) ?

The integral of 5/(x-6) is 5ln|x-6|+C

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integral of 5/(x-6)

\int \frac{5}{x - 6} d x

5 ln ∣ x - 6 ∣ + C

Solution steps

\int \frac{5}{x - 6} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{1}{x - 6} d x

Apply u-substitution

: \int \frac{1}{u} d u

= 5 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 5 ln ∣ u ∣

Substitute back

u = x - 6

= 5 ln ∣ x - 6 ∣

Add a constant to the solution

= 5 ln ∣ x - 6 ∣ + C

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 e^{2 t}

\int 9 + y^{2} d y

f (x) = \frac{3}{x ^{2}}, at x = 2

\frac{\partial}{\partial x} (y^{3 x})

f (x) = x + 2, x, x = 1, x = 3