What is the derivative of 800sqrt(x^2-0.3x) ?

The derivative of 800sqrt(x^2-0.3x) is (400(2x-0.3))/(sqrt(x^2-0.3x))

What is the first derivative of 800sqrt(x^2-0.3x) ?

The first derivative of 800sqrt(x^2-0.3x) is (400(2x-0.3))/(sqrt(x^2-0.3x))

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Popular >

derivative of

800 x^{2} - 0.3 x

\frac{400 ( 2 x - 0.3 )}{x ^{2} - 0.3 x}

Solution steps

\frac{d}{d x} (800 x^{2} - 0.3 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 800 \frac{d}{d x} (x^{2} - 0.3 x)

Apply the chain rule:

\frac{1}{2 x ^{2} - 0.3 x} \frac{d}{d x} (x^{2} - 0.3 x)

= \frac{1}{2 x ^{2} - 0.3 x} \frac{d}{d x} (x^{2} - 0.3 x)

\frac{d}{d x} (x^{2} - 0.3 x) = 2 x - 0.3

= 800 \cdot \frac{1}{2 x ^{2} - 0.3 x} (2 x - 0.3)

Simplify

800 \cdot \frac{1}{2 x ^{2} - 0.3 x} (2 x - 0.3) : \frac{400 ( 2 x - 0.3 )}{x ^{2} - 0.3 x}

= \frac{400 ( 2 x - 0.3 )}{x ^{2} - 0.3 x}

\frac{d}{d x} (lo g_{3} (sec (x)))

f (x) = \frac{x}{1 + x ^{2}}, (0, 0)

\frac{d}{d x} (\frac{3 - sec ( x )}{tan ( x )})

\frac{\partial}{\partial y} (ln (x - 2 y + 3 z))

\int_{- e^{2}}^{- e} \frac{3}{x} d x

What is the derivative of 800sqrt(x^2-0.3x) ?
The derivative of 800sqrt(x^2-0.3x) is (400(2x-0.3))/(sqrt(x^2-0.3x))
What is the first derivative of 800sqrt(x^2-0.3x) ?
The first derivative of 800sqrt(x^2-0.3x) is (400(2x-0.3))/(sqrt(x^2-0.3x))