What is the tangent of f(x)=(x^3-4x)^8,(2,0) ?

The tangent of f(x)=(x^3-4x)^8,(2,0) is y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(x^3-4x)^8,(2,0)

tangent of

f (x) = (x^{3} - 4 x)^{8}, (2, 0)

y = 0

Solution steps

Find the slope of

f (x) = (x^{3} - 4 x)^{8} : \frac{df ( x )}{d x} = 8 (x^{3} - 4 x)^{7} (3 x^{2} - 4)

Compute the slope of

f (x) = (x^{3} - 4 x)^{8}

(2, 0) : m = 0

Find the line with slope m=

0

and passing through

(2, 0) : y = 0

y = 0

\int (3 y - 2 y^{- 3}) d y

x \to \infty lim (\frac{ln ( 3 x + 5 )}{ln ( 7 x + 3 ) + 1})

\frac{d x}{d t} + 7 x = 5 cos (2 t)

n = 1 \sum \infty \frac{n ^{3}}{4 ^{n}}

x \to 1 lim ([g (x) - 3 f (x)])

What is the tangent of f(x)=(x^3-4x)^8,(2,0) ?
The tangent of f(x)=(x^3-4x)^8,(2,0) is y=0