What is laplacetransform 8^t*t+10 ?

The answer to laplacetransform 8^t*t+10 is 1/((s-3ln(2))^2)+(10)/s

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laplacetransform 8^t*t+10

laplace transform

8^{t} \cdot t + 10

\frac{1}{( s - 3 ln ( 2 ) ) ^{2}} + \frac{10}{s}

Solution steps

L {8^{t} t + 10}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {8^{t} t} + L {10}

L {8^{t} t} : \frac{1}{( s - 3 ln ( 2 ) ) ^{2}}

L {10} : \frac{10}{s}

= \frac{1}{( s - 3 ln ( 2 ) ) ^{2}} + \frac{10}{s}

\frac{d}{d y} (tan (x^{2} + y))

x^{3} - 4

\int e^{2 x y} d x

\int cos (2 x) cos (x) d x

\int \frac{x}{( x ^{4} + 1 )} d x

What is laplacetransform 8^t*t+10 ?
The answer to laplacetransform 8^t*t+10 is 1/((s-3ln(2))^2)+(10)/s