What is the derivative of 7sin(2x+3tan(x-1)) ?

The derivative of 7sin(2x+3tan(x-1)) is 14cos(2x)+3sec^2(x-1)

What is the first derivative of 7sin(2x+3tan(x-1)) ?

The first derivative of 7sin(2x+3tan(x-1)) is 14cos(2x)+3sec^2(x-1)

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\frac{d}{d x} (7 sin (2 x) + 3 tan (x - 1))

14 cos (2 x) + 3 sec^{2} (x - 1)

Solution steps

\frac{d}{d x} (7 sin (2 x) + 3 tan (x - 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 sin (2 x)) + \frac{d}{d x} (3 tan (x - 1))

\frac{d}{d x} (7 sin (2 x)) = 14 cos (2 x)

\frac{d}{d x} (3 tan (x - 1)) = 3 sec^{2} (x - 1)

= 14 cos (2 x) + 3 sec^{2} (x - 1)

\int \frac{1}{( x ^{2} - 2 x + 5 ) ^{\frac{3}{2}}} d x

y^{^{'''}} - 5 y^{^{''}} - 22 y^{^{'}} + 56 y = 0

y = (x^{3} - 2) (x^{2} - 3 x + 1), (2, - 6)

\frac{d x}{d t} = 7 x

4 x + 3 x^{2}

What is the derivative of 7sin(2x+3tan(x-1)) ?
The derivative of 7sin(2x+3tan(x-1)) is 14cos(2x)+3sec^2(x-1)
What is the first derivative of 7sin(2x+3tan(x-1)) ?
The first derivative of 7sin(2x+3tan(x-1)) is 14cos(2x)+3sec^2(x-1)