What is the derivative of (2x-7)^5 ?

The derivative of (2x-7)^5 is 10(2x-7)^4

What is the first derivative of (2x-7)^5 ?

The first derivative of (2x-7)^5 is 10(2x-7)^4

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derivative of

(2 x - 7)^{5}

10 (2 x - 7)^{4}

Solution steps

\frac{d}{d x} ((2 x - 7)^{5})

Apply the chain rule:

5 (2 x - 7)^{4} \frac{d}{d x} (2 x - 7)

= 5 (2 x - 7)^{4} \frac{d}{d x} (2 x - 7)

\frac{d}{d x} (2 x - 7) = 2

= 5 (2 x - 7)^{4} \cdot 2

Simplify

= 10 (2 x - 7)^{4}

y^{^{''}} + 4 y = 2 x e^{3 x}, y (0) = 0, y^{^{'}} (0) = 0

y = 8 x^{2} - 6

f (x) = \frac{2}{4} x^{5} - \frac{1}{3} x^{3} + \frac{3}{6} x^{2} + \frac{1}{2} x

\frac{d}{d x} (arcsin (x^{6}))

2 y^{^{''}} + 5 y^{^{'}} + 3 y = e^{- t}

What is the derivative of (2x-7)^5 ?
The derivative of (2x-7)^5 is 10(2x-7)^4
What is the first derivative of (2x-7)^5 ?
The first derivative of (2x-7)^5 is 10(2x-7)^4