What is 1/((z-1))*1/(e^{z+1)} ?

The solution to 1/((z-1))*1/(e^{z+1)} is 1/(e^{z+1)(z-1)}

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simplify 1/((z-1))*1/(e^{z+1)}

simplify

\frac{1}{( z - 1 )} \cdot \frac{1}{e ^{z + 1}}

\frac{1}{e ^{z + 1} ( z - 1 )}

Solution steps

\frac{1}{z - 1} \cdot \frac{1}{e ^{z + 1}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{( z - 1 ) e ^{z + 1}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{e ^{z + 1} ( z - 1 )}

\int \frac{x + 4}{x ^{2} + 25} d x

\frac{d}{d x} (2 0^{x})

\frac{\partial}{\partial x} (x e^{y} + 2 y)

\int 4 x ln (x) d x

What is 1/((z-1))*1/(e^{z+1)} ?
The solution to 1/((z-1))*1/(e^{z+1)} is 1/(e^{z+1)(z-1)}