What is the integral of 0.03e^{0.05x} ?

The integral of 0.03e^{0.05x} is 0.6e^{0.05x}+C

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integral of 0.03e^{0.05x}

\int 0.03 e^{0.05 x} d x

0.6 e^{0.05 x} + C

Solution steps

\int 0.03 e^{0.05 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.03 \cdot \int e^{0.05 x} d x

Apply u-substitution

: \int e^{u} \frac{1}{0.05} d u

= 0.03 \cdot \int e^{u} \frac{1}{0.05} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.03 \cdot \frac{1}{0.05} \cdot \int e^{u} d u

Simplify

= 0.03 \cdot 20 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 0.03 \cdot 20 e^{u}

Substitute back

u = 0.05 x

= 0.03 \cdot 20 e^{0.05 x}

Simplify

= 0.6 e^{0.05 x}

Add a constant to the solution

= 0.6 e^{0.05 x} + C

f (x) = \frac{9 ( 5 ^{x} )}{x ^{5}}

\int lo g_{x} (x) d x

\int \frac{5 x ^{2} - 3}{x ( x ^{2} - 1 )} d x

f (x) = \frac{4 x ^{2} + 8 x + 8}{x}

\frac{\partial}{\partial y} (x e^{x})

What is the integral of 0.03e^{0.05x} ?
The integral of 0.03e^{0.05x} is 0.6e^{0.05x}+C