What is join (2pir^2)+((80)/r) ?

The solution to join (2pir^2)+((80)/r) is (2pir^3+80)/r

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

join (2pir^2)+((80)/r)

join

(2 π r^{2}) + (\frac{80}{r})

\frac{2 π r ^{3} + 80}{r}

Solution steps

(2 π r^{2}) + (\frac{80}{r})

Remove parentheses:

(a) = a

= 2 π r^{2} + \frac{80}{r}

Convert element to fraction:

2 π r^{2} = \frac{2 π r ^{2} r}{r}

= \frac{2 π r ^{2} r}{r} + \frac{80}{r}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 π r ^{2} r + 80}{r}

2 π r^{2} r + 80 = 2 π r^{3} + 80

= \frac{2 π r ^{3} + 80}{r}

\int_{0}^{6} \frac{3 t}{( t - 7 ) ^{2}} d t

\frac{d}{d x} (\frac{4 x ^{2} + 7 x ^{5}}{x})

x \to 0 lim (\frac{2}{2 x})

\frac{d v}{d t} = 9.8 - 1.2 v

\int_{0}^{1} - 6 (x^{2} + 1) e^{- x} d x

What is join (2pir^2)+((80)/r) ?
The solution to join (2pir^2)+((80)/r) is (2pir^3+80)/r