What is the d/(d{x)}(200e^{-{x}^2-3{y}^2-9{z}^2}) ?

The d/(d{x)}(200e^{-{x}^2-3{y}^2-9{z}^2}) is -400e^{-{x}^2-3{y}^2-9{z}^2}{x}

What is the first d/(d{x)}(200e^{-{x}^2-3{y}^2-9{z}^2}) ?

The first d/(d{x)}(200e^{-{x}^2-3{y}^2-9{z}^2}) is -400e^{-{x}^2-3{y}^2-9{z}^2}{x}

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Popular >

\frac{d}{d x} (200 e^{- x^{2} - 3 y^{2} - 9 z^{2}})

- 400 e^{- x^{2} - 3 y^{2} - 9 z^{2}} x

Solution steps

\frac{d}{d x} (200 e^{- x^{2} - 3 y^{2} - 9 z^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 200 \frac{d}{d x} (e^{- x^{2} - 3 y^{2} - 9 z^{2}})

Apply the chain rule:

e^{- x^{2} - 3 y^{2} - 9 z^{2}} \frac{d}{d x} (- x^{2} - 3 y^{2} - 9 z^{2})

= e^{- x^{2} - 3 y^{2} - 9 z^{2}} \frac{d}{d x} (- x^{2} - 3 y^{2} - 9 z^{2})

\frac{d}{d x} (- x^{2} - 3 y^{2} - 9 z^{2}) = - 2 x

= 200 e^{- x^{2} - 3 y^{2} - 9 z^{2}} (- 2 x)

Simplify

= - 400 e^{- x^{2} - 3 y^{2} - 9 z^{2}} x

\frac{\partial}{\partial y} (x^{2} y)

\frac{d}{d x} (e^{4 x} sin (x))

y = 5 x

\int_{0}^{1} (1 - x^{2})^{0.5} d x

f (x) = \frac{x ^{2} + 32 x}{8}

What is the d/(d{x)}(200e^{-{x}^2-3{y}^2-9{z}^2}) ?
The d/(d{x)}(200e^{-{x}^2-3{y}^2-9{z}^2}) is -400e^{-{x}^2-3{y}^2-9{z}^2}{x}
What is the first d/(d{x)}(200e^{-{x}^2-3{y}^2-9{z}^2}) ?
The first d/(d{x)}(200e^{-{x}^2-3{y}^2-9{z}^2}) is -400e^{-{x}^2-3{y}^2-9{z}^2}{x}