What is the derivative of-x^4+2x^3+4x^2 ?

The derivative of-x^4+2x^3+4x^2 is -4x^3+6x^2+8x

What is the first derivative of-x^4+2x^3+4x^2 ?

The first derivative of-x^4+2x^3+4x^2 is -4x^3+6x^2+8x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

- x^{4} + 2 x^{3} + 4 x^{2}

- 4 x^{3} + 6 x^{2} + 8 x

Solution steps

\frac{d}{d x} (- x^{4} + 2 x^{3} + 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{4}) + \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

= - 4 x^{3} + 6 x^{2} + 8 x

f (x) = 3 x^{2} + 2

\int 2^{l n (x)} d x

f (x) = x - 2

\int_{0}^{L} sin^{2} (\frac{π x}{L}) d x

\frac{d}{d x} ((\frac{3}{5} x)^{3})

What is the derivative of-x^4+2x^3+4x^2 ?
The derivative of-x^4+2x^3+4x^2 is -4x^3+6x^2+8x
What is the first derivative of-x^4+2x^3+4x^2 ?
The first derivative of-x^4+2x^3+4x^2 is -4x^3+6x^2+8x