What is inverse oflaplace (10)/(s^3) ?

The answer to inverse oflaplace (10)/(s^3) is 5t^2

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inverse oflaplace (10)/(s^3)

inverse laplace

\frac{10}{s ^{3}}

5 t^{2}

Solution steps

L^{- 1} {\frac{10}{s ^{3}}}

= L^{- 1} {5 \cdot \frac{2}{s ^{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 5 L^{- 1} {\frac{2}{s ^{3}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{2}{s ^{3}}} = t^{2}

= 5 t^{2}

x \to \infty lim (x^{2} + 12)

\frac{d}{d x} (\frac{π x}{4})

45 (1 - e^{- 625 x})

f (x) = \frac{1}{1 + x ^{2}}, (2, \frac{2}{5})

\frac{d}{d x} (x^{2} (3 x - 4)^{3})

What is inverse oflaplace (10)/(s^3) ?
The answer to inverse oflaplace (10)/(s^3) is 5t^2