What is the derivative of 3x^{2/3}-x ?

The derivative of 3x^{2/3}-x is 2/(x^{1/3)}-1

What is the first derivative of 3x^{2/3}-x ?

The first derivative of 3x^{2/3}-x is 2/(x^{1/3)}-1

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\frac{d}{d x} (3 x^{\frac{2}{3}} - x)

\frac{2}{x ^{\frac{1}{3}}} - 1

Solution steps

\frac{d}{d x} (3 x^{\frac{2}{3}} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{\frac{2}{3}}) - \frac{d x}{d x}

\frac{d}{d x} (3 x^{\frac{2}{3}}) = \frac{2}{x ^{\frac{1}{3}}}

\frac{d x}{d x} = 1

= \frac{2}{x ^{\frac{1}{3}}} - 1

\frac{d}{d x} ((2 x + 1)^{- 1})

\int \frac{arcsin ( x )}{x} d x

y^{^{''}} + 16 y^{^{'}} + 80 y = 0

\frac{d}{d x} (- x^{3} + 3 x^{2} + 9 x - 1)

e^{2 x}, - 2

What is the derivative of 3x^{2/3}-x ?
The derivative of 3x^{2/3}-x is 2/(x^{1/3)}-1
What is the first derivative of 3x^{2/3}-x ?
The first derivative of 3x^{2/3}-x is 2/(x^{1/3)}-1