What is the derivative of cx+ln(cos(x)) ?

The derivative of cx+ln(cos(x)) is c-tan(x)

What is the first derivative of cx+ln(cos(x)) ?

The first derivative of cx+ln(cos(x)) is c-tan(x)

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\frac{d}{d x} (c x + ln (cos (x)))

c - tan (x)

Solution steps

\frac{d}{d x} (c x + ln (cos (x)))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (c x) + \frac{d}{d x} (ln (cos (x)))

\frac{d}{d x} (c x) = c

\frac{d}{d x} (ln (cos (x))) = - tan (x)

= c - tan (x)

y^{^{'}} + r y^{^{''}} = 0

\frac{d}{d x} ((x^{2} + 2)^{- 5} (cos (x)))

\int_{1200}^{1210} 0.1 x^{2} d x

(\frac{x ^{2} + 1}{x ^{2} - 1})^{7}

\frac{d}{d x} ((x^{3} - 3 x) (2 x^{2} + 3 x + 5))

What is the derivative of cx+ln(cos(x)) ?
The derivative of cx+ln(cos(x)) is c-tan(x)
What is the first derivative of cx+ln(cos(x)) ?
The first derivative of cx+ln(cos(x)) is c-tan(x)