What is the sum from n=0 to infinity of 1/(3^n) ?

The sum from n=0 to infinity of 1/(3^n) is 3/2

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sum from n=0 to infinity of 1/(3^n)

n = 0 \sum \infty \frac{1}{3 ^{n}}

\frac{3}{2}

Solution steps

n = 0 \sum \infty \frac{1}{3 ^{n}}

Apply Series Geometric Test:

\frac{3}{2}

= \frac{3}{2}

\int \frac{15}{25 + x ^{2}} d x

x \to - 2 lim (\frac{2}{x + 2})

\frac{d y}{d t} - 2 y = e^{2 t}

\int x^{5} (x^{6} - 10)^{4} d x

What is the sum from n=0 to infinity of 1/(3^n) ?
The sum from n=0 to infinity of 1/(3^n) is 3/2