What is the derivative of ln(e^{7x-2}) ?

The derivative of ln(e^{7x-2}) is 7

What is the first derivative of ln(e^{7x-2}) ?

The first derivative of ln(e^{7x-2}) is 7

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derivative of

ln (e^{7 x - 2})

7

Solution steps

\frac{d}{d x} (ln (e^{7 x - 2}))

Simplify

ln (e^{7 x - 2}) : 7 x - 2

= \frac{d}{d x} (7 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x) - \frac{d}{d x} (2)

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (2) = 0

= 7 - 0

Simplify

= 7

y^{^{''}} + 4 y^{^{'}} + 10 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\frac{d}{d x} (\frac{1}{2 + cos ( x )})

\frac{d}{d y} (e^{y} y^{e})

\int 4 e^{x} cos (2 x) d x

f (x) = (1 + 3 x) (5 - 2 x), at x = 2

What is the derivative of ln(e^{7x-2}) ?
The derivative of ln(e^{7x-2}) is 7
What is the first derivative of ln(e^{7x-2}) ?
The first derivative of ln(e^{7x-2}) is 7