What is the derivative of (10/9)t^2 ?

The derivative of (10/9)t^2 is (20t)/9

What is the first derivative of (10/9)t^2 ?

The first derivative of (10/9)t^2 is (20t)/9

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derivative of

(\frac{10}{9}) t^{2}

\frac{20 t}{9}

Solution steps

\frac{d}{d t} (\frac{10}{9} t^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{10}{9} \frac{d}{d t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{10}{9} \cdot 2 t^{2 - 1}

Simplify

\frac{10}{9} \cdot 2 t^{2 - 1} : \frac{20 t}{9}

= \frac{20 t}{9}

5 y^{^{''}} + y^{^{'}} = - 6 x

\frac{\partial}{\partial x} (y - 3 x)

x \to 0 lim (\frac{x}{sin ( π x )})

x \to - \infty lim (x^{5})

x \to 1 lim (3 x^{2} + 2 x + 1)

What is the derivative of (10/9)t^2 ?
The derivative of (10/9)t^2 is (20t)/9
What is the first derivative of (10/9)t^2 ?
The first derivative of (10/9)t^2 is (20t)/9