What is laplacetransform cos(3t+5) ?

The answer to laplacetransform cos(3t+5) is (cos(5)s-3sin(5))/(s^2+9)

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laplacetransform cos(3t+5)

laplace transform

cos (3 t + 5)

\frac{cos ( 5 ) s - 3 sin ( 5 )}{s ^{2} + 9}

Solution steps

L {cos (3 t + 5)}

Use Laplace Transform table:

L {cos (a t + b)} = \frac{s \cdot cos ( b ) - a \cdot sin ( b )}{s ^{2} + a ^{2}}

L {cos (3 t + 5)} = \frac{s cos ( 5 ) - 3 sin ( 5 )}{s ^{2} + 3 ^{2}}

= \frac{s cos ( 5 ) - 3 sin ( 5 )}{s ^{2} + 3 ^{2}}

= \frac{cos ( 5 ) s - 3 sin ( 5 )}{s ^{2} + 9}

x \to - 2 + lim (2 x + 2 + x)

x^{2} + x + 4

y^{^{''}} - 3 y^{^{'}} + 7 y = 4 e^{3 t}

\frac{d}{d x} (\frac{8.7 x + 0.2}{x ^{2} - 4.5 x + 7.5})

What is laplacetransform cos(3t+5) ?
The answer to laplacetransform cos(3t+5) is (cos(5)s-3sin(5))/(s^2+9)