What is the solution for y^{'''}+13y^{''}-9y^'-405y=0 ?

The solution for y^{'''}+13y^{''}-9y^'-405y=0 is y=c_{1}e^{5t}+c_{2}e^{-9t}+c_{3}te^{-9t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}+13y^{''}-9y^'-405y=0

y^{^{'''}} + 13 y^{^{''}} - 9 y^{^{'}} - 405 y = 0

y = c_{1} e^{5 t} + c_{2} e^{- 9 t} + c_{3} t e^{- 9 t}

Solution steps

y^{'''} (t) + 13 y^{''} (t) - 9 y^{'} (t) - 405 y = 0

Solve linear ODE:

y = c_{1} e^{5 t} + c_{2} e^{- 9 t} + c_{3} t e^{- 9 t}

y = c_{1} e^{5 t} + c_{2} e^{- 9 t} + c_{3} t e^{- 9 t}

y^{^{'}} = 3 - \frac{2 y}{200 + x}

\int \frac{2 + x}{9 + x ^{2}} d x

\int \frac{2}{( 25 + x ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{1}{6} sin (6 x) d x

y^{^{''}} + a y^{^{'}} + b y = 0

What is the solution for y^{'''}+13y^{''}-9y^'-405y=0 ?
The solution for y^{'''}+13y^{''}-9y^'-405y=0 is y=c_{1}e^{5t}+c_{2}e^{-9t}+c_{3}te^{-9t}