What is the integral of 3cot(x) ?

The integral of 3cot(x) is 3ln|sin(x)|+C

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integral of 3cot(x)

\int 3 cot (x) d x

3 ln ∣ sin (x) ∣ + C

Solution steps

\int 3 cot (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int cot (x) d x

Rewrite using trig identities

= 3 \cdot \int \frac{cos ( x )}{sin ( x )} d x

Apply u-substitution

: \int \frac{1}{u} d u

= 3 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 3 ln ∣ u ∣

Substitute back

u = sin (x)

= 3 ln ∣ sin (x) ∣

Add a constant to the solution

= 3 ln ∣ sin (x) ∣ + C

\int sin (\frac{1}{4} x) d x

\frac{\partial}{\partial x} ((x - u)^{2})

x \to 3 lim ((x - 3)^{2})

\frac{d}{d x} (e^{- 3 x^{4}} \cdot ln (7 x^{2}))

\frac{\partial}{\partial y} (\frac{x}{y ^{2}})