What is the derivative of f(x)=(x+1)^2 ?

The derivative of f(x)=(x+1)^2 is 2(x+1)

What is the first derivative of f(x)=(x+1)^2 ?

The first derivative of f(x)=(x+1)^2 is 2(x+1)

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derivative of

f (x) = (x + 1)^{2}

2 (x + 1)

Solution steps

\frac{d}{d x} ((x + 1)^{2})

Apply the chain rule:

2 (x + 1) \frac{d}{d x} (x + 1)

= 2 (x + 1) \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 2 (x + 1) \cdot 1

Simplify

= 2 (x + 1)

y^{^{''}} + 324 y = sec (18 x)

x \to 18 lim (\frac{x ^{2}}{2} - \frac{9}{x})

y^{^{'}} = 2 (3 x + y)^{2} - 1

\int_{1}^{2} \frac{x + 2 x ^{2}}{x} d x

n = 2 \sum \infty \frac{1}{n + 1}

What is the derivative of f(x)=(x+1)^2 ?
The derivative of f(x)=(x+1)^2 is 2(x+1)
What is the first derivative of f(x)=(x+1)^2 ?
The first derivative of f(x)=(x+1)^2 is 2(x+1)