What is taylor 5+xe^{3x} ?

The answer to taylor 5+xe^{3x} is 5+x+3x^2+9/2 x^3+9/2 x^4+\ldots

Popular >

taylor 5+xe^{3x}

taylor

5 + x e^{3 x}

5 + x + 3 x^{2} + \frac{9}{2} x^{3} + \frac{9}{2} x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 5 + \frac{\frac{d}{d x} ( 5 + x e ^{3 x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 5 + x e ^{3 x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 5 + x e ^{3 x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 5 + \frac{1}{1 !} x + \frac{6}{2 !} x^{2} + \frac{27}{3 !} x^{3} + \frac{108}{4 !} x^{4} + \dots

Refine

= 5 + x + 3 x^{2} + \frac{9}{2} x^{3} + \frac{9}{2} x^{4} + \dots

\int \frac{2 sin ( x )}{cos ^{4} ( x )} d x

\frac{\partial}{\partial x} ((m - x)^{2} + y^{2})

x \to 3 lim (\frac{4 x + 8}{x - 5})

y = e^{x}, at x = 0

\frac{d}{d x} (\frac{200}{1 + e ^{5 - x}})

What is taylor 5+xe^{3x} ?
The answer to taylor 5+xe^{3x} is 5+x+3x^2+9/2 x^3+9/2 x^4+\ldots