What is the solution for (dv)/(dt)=k\sqrt[3]{v^2},v(0)=27 ?

The solution for (dv)/(dt)=k\sqrt[3]{v^2},v(0)=27 is v=(k^3t^3)/(27)+k^2t^2+9kt+27

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dv)/(dt)=k\sqrt[3]{v^2},v(0)=27

v = \frac{k ^{3} t ^{3}}{27} + k^{2} t^{2} + 9 k t + 27

Solution steps

Solve separable ODE:

v = \frac{k ^{3} t ^{3}}{27} + k^{2} t^{2} + 9 k t + 27

v = \frac{k ^{3} t ^{3}}{27} + k^{2} t^{2} + 9 k t + 27

\frac{d}{d x} (e^{s i n (x)} \cdot cos (x))

\int x y x^{2} + y^{2} d y

y = x + \frac{2}{x}

\int_{0}^{4} \frac{x}{2 x + 1} d x

x \to 0 + lim (\frac{5}{x + x ^{2}})

What is the solution for (dv)/(dt)=k\sqrt[3]{v^2},v(0)=27 ?
The solution for (dv)/(dt)=k\sqrt[3]{v^2},v(0)=27 is v=(k^3t^3)/(27)+k^2t^2+9kt+27