What is the integral from 1 to e of ln(7x) ?

The integral from 1 to e of ln(7x) is eln(7e)-e-ln(7)+1

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integral from 1 to e of ln(7x)

\int_{1}^{e} ln (7 x) d x

e ln (7 e) - e - ln (7) + 1

Decimal Notation

4.34362 \dots

Solution steps

\int_{1}^{e} ln (7 x) d x

Apply Integration By Parts

: [x ln (7 x) - \int 1 d x]_{1}^{e}

= [x ln (7 x) - \int 1 d x]_{1}^{e}

\int 1 d x = x

= [x ln (7 x) - x]_{1}^{e}

Compute the boundaries:

e ln (7 e) - e - ln (7) + 1

= e ln (7 e) - e - ln (7) + 1

\frac{d}{d x} (e^{x} cos (4 x))

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x \to 2 lim (- x^{2} + 7 x - 2)

\int 8 x^{3} sin (1 - x^{4}) d x

What is the integral from 1 to e of ln(7x) ?
The integral from 1 to e of ln(7x) is eln(7e)-e-ln(7)+1