What is the integral of (x^{1.3}+7x^{2.5}) ?

The integral of (x^{1.3}+7x^{2.5}) is 0.43478…x^{2.3}+2x^{3.5}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^{1.3}+7x^{2.5})

\int (x^{1.3} + 7 x^{2.5}) d x

0.43478 \dots x^{2.3} + 2 x^{3.5} + C

Solution steps

\int x^{1.3} + 7 x^{2.5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{1.3} d x + \int 7 x^{2.5} d x

\int x^{1.3} d x = 0.43478 \dots x^{2.3}

\int 7 x^{2.5} d x = 2 x^{3.5}

= 0.43478 \dots x^{2.3} + 2 x^{3.5}

Add a constant to the solution

= 0.43478 \dots x^{2.3} + 2 x^{3.5} + C

\int_{1}^{5} \frac{24 + x ^{2}}{x} d x

\frac{d}{d x} (\frac{ln ( x )}{x ^{8}})

\frac{\partial}{\partial x} (\frac{47 x y}{x - y})

\frac{d}{d x} (sec (x) csc (x))

x, 1 - x, - \frac{x}{2}

What is the integral of (x^{1.3}+7x^{2.5}) ?
The integral of (x^{1.3}+7x^{2.5}) is 0.43478…x^{2.3}+2x^{3.5}+C