What is the derivative of 9x^3(x^2-2) ?

The derivative of 9x^3(x^2-2) is 9(5x^4-6x^2)

What is the first derivative of 9x^3(x^2-2) ?

The first derivative of 9x^3(x^2-2) is 9(5x^4-6x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

9 x^{3} (x^{2} - 2)

9 (5 x^{4} - 6 x^{2})

Solution steps

\frac{d}{d x} (9 x^{3} (x^{2} - 2))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x^{3} (x^{2} - 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = x^{2} - 2

= 9 (\frac{d}{d x} (x^{3}) (x^{2} - 2) + \frac{d}{d x} (x^{2} - 2) x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2} - 2) = 2 x

= 9 (3 x^{2} (x^{2} - 2) + 2 x x^{3})

Simplify

9 (3 x^{2} (x^{2} - 2) + 2 x x^{3}) : 9 (5 x^{4} - 6 x^{2})

= 9 (5 x^{4} - 6 x^{2})

f (x) = \frac{( x + 1 ) ^{2}}{3 x - 4}

\int \frac{3 - 18 x}{4 - 9 x ^{2}} d x

\int \frac{1}{( 1 - 6 x ) ^{4}} d x

\frac{( s + 1 )}{( s ^{2} + s + 1 )}

x \to + 4 lim (5)

What is the derivative of 9x^3(x^2-2) ?
The derivative of 9x^3(x^2-2) is 9(5x^4-6x^2)
What is the first derivative of 9x^3(x^2-2) ?
The first derivative of 9x^3(x^2-2) is 9(5x^4-6x^2)