What is the derivative of y=x^3+3x^2 ?

The derivative of y=x^3+3x^2 is 3x^2+6x

What is the first derivative of y=x^3+3x^2 ?

The first derivative of y=x^3+3x^2 is 3x^2+6x

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derivative of

y = x^{3} + 3 x^{2}

3 x^{2} + 6 x

Solution steps

\frac{d}{d x} (x^{3} + 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

= 3 x^{2} + 6 x

\frac{\partial}{\partial x} (2 cos (y))

\frac{1}{5 x ^{2}}

\frac{\partial}{\partial x} (tan (3 x))

y^{^{''}} - 9 y^{^{'}} + 20 y = 0

x \to 4 lim (\frac{x - 5}{x - 4})

What is the derivative of y=x^3+3x^2 ?
The derivative of y=x^3+3x^2 is 3x^2+6x
What is the first derivative of y=x^3+3x^2 ?
The first derivative of y=x^3+3x^2 is 3x^2+6x