What is the integral of (e^{-y})/y ?

The integral of (e^{-y})/y is \Ei(-y)+C

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integral of (e^{-y})/y

\int \frac{e ^{- y}}{y} d y

Ei (- y) + C

Solution steps

\int \frac{e ^{- y}}{y} d y

Apply u-substitution

: \int \frac{e ^{u}}{u} d u

= \int \frac{e ^{u}}{u} d u

Use the nonelementary integral:

\int \frac{e ^{x}}{x} d x = Ei (x)

= Ei (u)

Substitute back

u = - y

= Ei (- y)

Add a constant to the solution

= Ei (- y) + C

\int_{0}^{2} (x - 1)^{2} d x

\frac{\partial}{\partial x} (5 - x^{2} + x y - 2^{2})

\frac{d}{d x} ((x^{3} + 4)^{- 3})

x \to 0 + lim (6 - \frac{1}{x ^{2}})