What is the derivative of y=4x^{2/3}+6x^{1/2}-8 ?

The derivative of y=4x^{2/3}+6x^{1/2}-8 is 8/(3x^{1/3)}+3/(x^{1/2)}

What is the first derivative of y=4x^{2/3}+6x^{1/2}-8 ?

The first derivative of y=4x^{2/3}+6x^{1/2}-8 is 8/(3x^{1/3)}+3/(x^{1/2)}

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derivative of

y = 4 x^{\frac{2}{3}} + 6 x^{\frac{1}{2}} - 8

\frac{8}{3 x ^{\frac{1}{3}}} + \frac{3}{x ^{\frac{1}{2}}}

Solution steps

\frac{d}{d x} (4 x^{\frac{2}{3}} + 6 x^{\frac{1}{2}} - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{\frac{2}{3}}) + \frac{d}{d x} (6 x^{\frac{1}{2}}) - \frac{d}{d x} (8)

\frac{d}{d x} (4 x^{\frac{2}{3}}) = \frac{8}{3 x ^{\frac{1}{3}}}

\frac{d}{d x} (6 x^{\frac{1}{2}}) = \frac{3}{x ^{\frac{1}{2}}}

\frac{d}{d x} (8) = 0

= \frac{8}{3 x ^{\frac{1}{3}}} + \frac{3}{x ^{\frac{1}{2}}} - 0

Simplify

= \frac{8}{3 x ^{\frac{1}{3}}} + \frac{3}{x ^{\frac{1}{2}}}

\int 8 x + 3 d x

\frac{d r}{d θ} + r tan (θ) = sec (θ)

f (x) = 6 sin (x) - 4 x cos (x) - x^{2} sin (x)

\frac{\partial}{\partial y} (50 y + 3000 - 100 x)

\frac{\partial}{\partial x} (\frac{59}{( 1 + x ^{2} + y ^{2} )})

What is the derivative of y=4x^{2/3}+6x^{1/2}-8 ?
The derivative of y=4x^{2/3}+6x^{1/2}-8 is 8/(3x^{1/3)}+3/(x^{1/2)}
What is the first derivative of y=4x^{2/3}+6x^{1/2}-8 ?
The first derivative of y=4x^{2/3}+6x^{1/2}-8 is 8/(3x^{1/3)}+3/(x^{1/2)}