What is the slope of (1-x-x^2)(x-2),\at x=1 ?

The slope of (1-x-x^2)(x-2),\at x=1 is 2

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slope of (1-x-x^2)(x-2),\at x=1

slope

(1 - x - x^{2}) (x - 2), at x = 1

2

Solution steps

y = (1 - x - x^{2}) (x - 2)

In order to find the slope of the function, take the derivative of

(1 - x - x^{2}) (x - 2)

\frac{d}{d x} ((1 - x - x^{2}) (x - 2)) = - 3 x^{2} + 2 x + 3

- 3 x^{2} + 2 x + 3

Find the value of

- 3 x^{2} + 2 x + 3

for

x = 1 : 2

2

(1 + x^{2}) y^{^{'}} + 4 x y = x, y (0) = 1

\int \frac{2}{( 1 - 2 x ) ^{2}} d x

\int_{- 1}^{0} e^{- x} d x

\frac{d}{d x} (5 tan (3 x))

1, \frac{1}{x}, 1, 2

What is the slope of (1-x-x^2)(x-2),\at x=1 ?
The slope of (1-x-x^2)(x-2),\at x=1 is 2